NTH_VALUE
声明
NTH_VALUE (measure_expr, n) [ FROM { FIRST | LAST } ] [ { RESPECT | IGNORE } NULLS ] OVER (analytic_clause)
说明
返回表达式 expr 的第 n 个值,方向由 [ FROM { FIRST | LAST } ] 确定,默认为 FROM FIRST,含有 是否忽略 NULL 值的标志。其窗口为统一的 analytic_clause。
其中,n 必须为正数,如果 n 是 NULL,函数将返回错误;如果 n 大于窗口内所有的行数,此函数将返回 NULL。
示例
CREATE TABLE EXPLOYEES(LAST_NAME CHAR(10), SALARY DECIMAL, JOB_ID CHAR(32));
Query OK, 0 rows affected (0.036 sec)
INSERT INTO EXPLOYEES VALUES('JIM', 2000, 'CLEANER');
Query OK, 1 row affected (0.001 sec)
INSERT INTO EXPLOYEES VALUES('MIKE', 12000, 'ENGINEERING');
Query OK, 1 row affected (0.001 sec)
INSERT INTO EXPLOYEES VALUES('LILY', 13000, 'ENGINEERING');
Query OK, 1 row affected (0.001 sec)
INSERT INTO EXPLOYEES VALUES('TOM', 11000, 'ENGINEERING');
Query OK, 1 row affected (00.001 sec)
SELECT LAST_NAME, FIRST_VALUE(SALARY) OVER(PARTITION BY JOB_ID) FIRST_S, LAST_VALUE(SALARY) OVER(PARTITION BY JOB_ID) LAST_S, NTH_VALUE(SALARY,2) OVER(PARTITION BY JOB_ID) 2ND_S FROM EXPLOYEES;
+-----------+---------+--------+-------+
| LAST_NAME | FIRST_S | LAST_S | 2ND_S |
+-----------+---------+--------+-------+
| JIM | 2000 | 2000 | NULL |
| MIKE | 12000 | 11000 | 13000 |
| LILY | 12000 | 11000 | 13000 |
| TOM | 12000 | 11000 | 13000 |
+-----------+---------+--------+-------+
4 rows in set (0.003 sec)